1/√(1-x) =2
√(1-x)=1/2
1-x=(1/2)²
1-x=1/4
x2=3/4
t=√(1-x); x=1-t²; dx=-2tdt; ∫dx/√(1-x)=-2∫(t/t)dt=-2t+C=-2√(1-x)+C
3/4 3/4
∫(2-1/√(1-x) )dx =2х+2√(1-x)| =2*3/4+2√(1-3/4)-(2*0+2√(1-0))=
0 0
=3/2+2√1/4-2√1=3/2+2*1/2-2=3/2+1-2=1/2
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