2a
ʃsin2xdx=√3a-1
a
2a
-1/2 cos(2x)| =√3a-1
a
-1/2cos(2*2a)-(-1/2)cos(2*a)=√3a-1
-1/2cos(4a)+1/2cos(2a)=√3a-1
-1/2*(8cos^4(a) - 8cos^2(a) + 1 ) +1/2*(2Cos^2(a)-1)=√3a-1
-4cos^4(a)+4cos^2(a)-1/2+2cos^2a-1/2=√3a-1
-4cos^4(a)+6cos^2(a)=√3a-1+1/2+1/2
-4cos^4(a)+6cos^2(a)=√3a
2cos^2(a)(-2cos^2(a)-3)=√3a
