E=E°+((R*T)/(n*F))*lg[Men+]
n(Ag+1)=1
R*T/F=0.06
E°(Ag)=0.8
lg[0,001]=-3
lg[0,1]=-1
E(0.001)=0.8+(0.06/1)*(-3)=0.8-0.18=0.62В
E(0.1)=0.8+(0.06/1)*(-1)=0.8-0.06=0.74В
n(Ag+1)=1
R*T/F=0.06
E°(Ag)=0.8
lg[0,001]=-3
lg[0,1]=-1
E(0.001)=0.8+(0.06/1)*(-3)=0.8-0.18=0.62В
E(0.1)=0.8+(0.06/1)*(-1)=0.8-0.06=0.74В