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1) 26+5y+0,5y^2=2,5y^2+26               2)21z+11=11+17z-5y^2 берилгени осылайма?
26-5y-0,5y^2-2,5y^2-26                            21z+11-11-17z+5z^2
-5y-3y^2=0                                                 5z^2+4z=0
                                                                     z(5z+4)=0
y(5-3у)=0                                                     z=0
y=0                                                               5z=-4
-3y=-5                                                           z=5/-4   
y=-3/-5                                                           z=-1,25
y-0,6
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