2) х+2у+3=0 4х+5y+6=0
x=-2y-3 4*(-2y-3)+5y+6=0
x=-2*(-2)-3 -8y-12+5y+6=0
x=4-3 -3y-6=0
x=1 -3y=6
y=6/(-3)
y=-2
3)3x-y-2=0 және 2x+y-8=0
3x-8+2x-2=0 y=8-2x
5 x=8+2 y=8-2*2
5 x=10 y=4
x=2
4)4x+5y+8=0 және 4x-2y-6=02 емес 2 шығар
4x=-5y-8 4*((-5y-8)/2)-2y-6=2
x=(-5y-8)/2 -10y-16-2y-6=2
x=(-5*(-2)-8)/2 -12y=2+16+6
x=(10-8)/2 -12y=2+22
x=1 -12y=24
y=-2