Выражение: (x-2)*(x+3)+(x-3)*(x+2)+(x-3)*(x+2)
Ответ: 3*x^2-18-x
Решаем по действиям:
1. (x-2)*(x+3)=x^2+x-6
(x-2)*(x+3)=x*x+x*3-2*x-2*3
1.1. x*x=x^2
x*x=x^(1+1)
1.1.1. 1+1=2
+1
_1_
2
1.2. x*3-2*x=1*x
1.3. 2*3=6
X2
_3_
6
2. (x-3)*(x+2)=x^2-x-6
(x-3)*(x+2)=x*x+x*2-3*x-3*2
2.1. x*x=x^2
x*x=x^(1+1)
2.1.1. 1+1=2
+1
_1_
2
2.2. x*2-3*x=-1*x
2.3. 3*2=6
X3
_2_
6
3. x^2+x^2=2*x^2
4. x-x=0
5. -6-6=-12
+6
_6_
12
6. (x-3)*(x+2)=x^2-x-6
(x-3)*(x+2)=x*x+x*2-3*x-3*2
6.1. x*x=x^2
x*x=x^(1+1)
6.1.1. 1+1=2
+1
_1_
2
6.2. x*2-3*x=-1*x
6.3. 3*2=6
X3
_2_
6
7. 2*x^2+x^2=3*x^2
8. -12-6=-18
+12
_ _6_
18
Решаем по шагам:
1. x^2+x-6+(x-3)*(x+2)+(x-3)*(x+2)
1.1. (x-2)*(x+3)=x^2+x-6
(x-2)*(x+3)=x*x+x*3-2*x-2*3
1.1.1. x*x=x^2
x*x=x^(1+1)
1.1.1.1. 1+1=2
+1
_1_
2
1.1.2. x*3-2*x=1*x
1.1.3. 2*3=6
X2
_3_
6
2. x^2+x-6+x^2-x-6+(x-3)*(x+2)
2.1. (x-3)*(x+2)=x^2-x-6
(x-3)*(x+2)=x*x+x*2-3*x-3*2
2.1.1. x*x=x^2
x*x=x^(1+1)
2.1.1.1. 1+1=2
+1
_1_
2
2.1.2. x*2-3*x=-1*x
2.1.3. 3*2=6
X3
_2_
6
3. 2*x^2+x-6-x-6+(x-3)*(x+2)
3.1. x^2+x^2=2*x^2
4. 2*x^2-6-6+(x-3)*(x+2)
4.1. x-x=0
5. 2*x^2-12+(x-3)*(x+2)
5.1. -6-6=-12
+6
_6_
12
6. 2*x^2-12+x^2-x-6
6.1. (x-3)*(x+2)=x^2-x-6
(x-3)*(x+2)=x*x+x*2-3*x-3*2
6.1.1. x*x=x^2
x*x=x^(1+1)
6.1.1.1. 1+1=2
+1
_1_
2
6.1.2. x*2-3*x=-1*x
6.1.3. 3*2=6
X3
_2_
6
7. 3*x^2-12-x-6
7.1. 2*x^2+x^2=3*x^2
8. 3*x^2-18-x
8.1. -12-6=-18
+12
_ _6_
18
